JEE PYQ: Motion in a Straight Line - Question ID f3d492a1be57 (JEE Main 2020)

ID: f3d492a1be57JEE Main 2020Numerical Value
The speed verses time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be________. JEE Main 2020 (Online) 4th September Evening Slot Physics - Motion in a Straight Line Question 90 English
JEE Question illustration f3d492a1be57

Your Answer

Step-by-step Explanation

Distance travelled = Area under speed – time graph

= 12×8×5{1 \over 2} \times 8 \times 5 = 20 m

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