JEE PYQ: Motion in a Straight Line - Question ID eacf43d26e4a (JEE Main 2024)

ID: eacf43d26e4aJEE Main 2024Single Correct MCQ

A body starts moving from rest with constant acceleration covers displacement S1S_1 in first (p1)(p-1) seconds and S2\mathrm{S}_2 in first pp seconds. The displacement S1+S2\mathrm{S}_1+\mathrm{S}_2 will be made in time :

Select Option

Step-by-step Explanation

Core Formula & Concept:

When a body starts from rest and moves with constant acceleration, its displacement ss in the first tt seconds is given by the kinematic equation: s=12at2.s = \tfrac{1}{2}\,a\,t^{2}. Here aa is the constant acceleration.

The problem gives two displacements: S1S_{1} in the first (p1)(p-1) seconds, and S2S_{2} in the first pp seconds. We are asked to find the time TT in which the body covers the combined displacement S1+S2S_{1}+S_{2}.

Step-by-Step Derivation:

1. Express S1S_{1} and S2S_{2} in terms of aa and pp.

S1=12a(p1)2,S2=12ap2.S_{1} = \tfrac{1}{2}\,a\,(p-1)^{2}, \quad S_{2} = \tfrac{1}{2}\,a\,p^{2}.

2. Compute the combined displacement S1+S2S_{1}+S_{2}.

S1+S2=12a[(p1)2+p2]=12a[p22p+1+p2]=12a[2p22p+1]=a(p2p+12).S_{1}+S_{2} = \tfrac{1}{2}\,a\bigl[(p-1)^{2} + p^{2}\bigr] = \tfrac{1}{2}\,a\bigl[p^{2}-2p+1 + p^{2}\bigr] = \tfrac{1}{2}\,a\bigl[2p^{2}-2p+1\bigr] = a\bigl(p^{2}-p+\tfrac{1}{2}\bigr).

3. Let TT be the time in which the body covers S1+S2S_{1}+S_{2}.

Using the same kinematic formula, S1+S2=12aT2.S_{1}+S_{2} = \tfrac{1}{2}\,a\,T^{2}. Equate the two expressions for S1+S2S_{1}+S_{2}: 12aT2=a(p2p+12).\tfrac{1}{2}\,a\,T^{2} = a\bigl(p^{2}-p+\tfrac{1}{2}\bigr). Cancel aa (nonzero) and multiply both sides by 22: T2=2(p2p+12)=2p22p+1.T^{2} = 2\bigl(p^{2}-p+\tfrac{1}{2}\bigr) = 2p^{2}-2p+1. Hence T=2p22p+1.T = \sqrt{2p^{2}-2p+1}.

4. Match with the given options.

The correct expression for TT is 2p22p+1s\sqrt{2p^{2}-2p+1}\,s, which corresponds to option D. Common Traps & Exam Tip:

• Many students mistakenly add the times (p1)+p(p-1)+p and try to use that sum directly, ignoring the quadratic nature of displacement under constant acceleration. • Others forget to take the square root at the end, leading them to choose option C instead of D. • Always write down the kinematic formula explicitly and substitute step by step to avoid sign or algebraic errors.

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