JEE PYQ: Motion in a Straight Line - Question ID eacf43d26e4a (JEE Main 2024)
A body starts moving from rest with constant acceleration covers displacement in first seconds and in first seconds. The displacement will be made in time :
Select Option
Step-by-step Explanation
When a body starts from rest and moves with constant acceleration, its displacement in the first seconds is given by the kinematic equation: Here is the constant acceleration.
The problem gives two displacements: in the first seconds, and in the first seconds. We are asked to find the time in which the body covers the combined displacement .
Step-by-Step Derivation:1. Express and in terms of and .
2. Compute the combined displacement .
3. Let be the time in which the body covers .
Using the same kinematic formula, Equate the two expressions for : Cancel (nonzero) and multiply both sides by : Hence4. Match with the given options.
The correct expression for is , which corresponds to option D. Common Traps & Exam Tip:• Many students mistakenly add the times and try to use that sum directly, ignoring the quadratic nature of displacement under constant acceleration. • Others forget to take the square root at the end, leading them to choose option C instead of D. • Always write down the kinematic formula explicitly and substitute step by step to avoid sign or algebraic errors.
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A particle starts moving from time and its coordinate is given as
A. The particle returns to its original position (origin) 0.866 units later
B. The particle is 1 unit away from origin at its turning point
C. Acceleration of the particle is non-negative
D. The particle is 0.5 units away from origin at its turning point
E. Particle never turns back as acceleration is non-negative
Choose the correct answer from the options given below :