JEE PYQ: Units & Measurements - Question ID e2e36b1b5242 (JEE Main 2021)

ID: e2e36b1b5242JEE Main 2021Single Correct MCQ
If time (t), velocity (v), and angular momentum (l) are taken as the fundamental units. Then the dimension of mass (m) in terms of t, v and l is :

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Step-by-step Explanation

Core Formula & Concept:

In dimensional analysis, we express any physical quantity in terms of fundamental (base) units. Here, the fundamental units are:

  • Time: tt
  • Velocity: vv
  • Angular momentum: ll
We need to express the dimension of mass (mm) in terms of these three fundamental units. Key formulas used:
  1. Velocity: v=displacementtime[v]=LTv = \frac{\text{displacement}}{\text{time}} \Rightarrow [v] = \frac{L}{T}
  2. Angular momentum: l=mvr[l]=[m][v][r]l = mvr \Rightarrow [l] = [m] \cdot [v] \cdot [r], where rr is distance (dimension LL)
  3. Mass is a base quantity in the standard SI system, but here we must express it in terms of tt, vv, and ll.


Step-by-Step Derivation:

Step 1: Express standard dimensions in terms of tt, vv, and ll
We know:

  • [v]=LTL=vT[v] = \frac{L}{T} \Rightarrow L = v \cdot T
  • [l]=mvr[l]=mvL[l] = m \cdot v \cdot r \Rightarrow [l] = m \cdot v \cdot L (since rr has dimension LL)
Substitute L=vtL = v \cdot t into the angular momentum dimension: [l]=mv(vt)=mv2t[l] = m \cdot v \cdot (v \cdot t) = m \cdot v^2 \cdot t Step 2: Solve for mass mm
Rearrange the equation to isolate mm: m=lv2tm = \frac{l}{v^2 \cdot t} Step 3: Express dimensionally
Thus, the dimension of mass in terms of tt, vv, and ll is: [m]=[t1v2l1][m] = [t^{-1} \cdot v^{-2} \cdot l^{1}] Step 4: Match with given options
Comparing with the options:
  • A: [t1v1l2][t^{-1} v^{1} l^{-2}] → Incorrect
  • B: [t1v2l1][t^{1} v^{2} l^{-1}] → Incorrect
  • C: [t2v1l1][t^{-2} v^{-1} l^{1}] → Incorrect
  • D: [t1v2l1][t^{-1} v^{-2} l^{1}] → Correct


Common Traps & Exam Tip:

Common Mistakes:

  • Students often confuse the dimension of angular momentum (l=mvrl = mvr) and forget that rr (distance) must be expressed in terms of vv and tt. This leads to incorrect exponents.
  • Some misapply the formula for momentum (p=mvp = mv) instead of angular momentum, leading to wrong dimensions.
  • Sign errors in exponents (e.g., writing v2v^2 instead of v2v^{-2}) are frequent.
Exam Tip:
Always start by writing the defining formula of the given fundamental units (here, v=LTv = \frac{L}{T} and l=mvrl = mvr). Then systematically eliminate standard dimensions (MM, LL, TT) in favor of the new fundamental units (tt, vv, ll). Double-check each algebraic step to avoid sign and exponent errors.

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