JEE PYQ: Vector Algebra - Question ID de3c102ddb10 (JEE Main 2021)

ID: de3c102ddb10JEE Main 2021Single Correct MCQ
The resultant of these forces OP,OQ,OR,OS\overrightarrow {OP} ,\overrightarrow {OQ} ,\overrightarrow {OR} ,\overrightarrow {OS} and OT\overrightarrow {OT} is approximately .......... N.

[Take 3=1.7\sqrt 3 = 1.7, 2=1.4\sqrt 2 = 1.4 Given i^\widehat i and j^\widehat j unit vectors along x, y axis]

JEE Main 2021 (Online) 27th August Morning Shift Physics - Vector Algebra Question 22 English
JEE Question illustration de3c102ddb10

Select Option

Step-by-step Explanation

JEE Main 2021 (Online) 27th August Morning Shift Physics - Vector Algebra Question 22 English Explanation
Fx=(10×32+20(12)+20(12)15(12)15(32))i^\overrightarrow {{F_x}} = \left( {10 \times {{\sqrt 3 } \over 2} + 20\left( {{1 \over 2}} \right) + 20\left( {{1 \over {\sqrt 2 }}} \right) - 15\left( {{1 \over {\sqrt 2 }}} \right) - 15\left( {{{\sqrt 3 } \over 2}} \right)} \right)\widehat i

=9.25i^= 9.25\widehat i

Fy=(15(12)+20(32)+10(12)15(12)20(12))j^\overrightarrow {{F_y}} = \left( {15\left( {{1 \over 2}} \right) + 20\left( {{{\sqrt 3 } \over 2}} \right) + 10\left( {{1 \over 2}} \right) - 15\left( {{1 \over {\sqrt 2 }}} \right) - 20\left( {{1 \over {\sqrt 2 }}} \right)} \right)\widehat j

=5j^= 5\widehat j