JEE PYQ: Units & Measurements - Question ID bbe2455d276c (JEE Main 2020)

ID: bbe2455d276cJEE Main 2020Single Correct MCQ
Dimensional formula for thermal conductivity is (here K denotes the temperature):

Select Option

Step-by-step Explanation

Core Formula & Concept:

Thermal conductivity (kk) is defined through Fourier’s law of heat conduction. The law states that the rate of heat flow (HH) through a material is proportional to the temperature gradient (dTdx\frac{dT}{dx}) and the cross-sectional area (AA) perpendicular to the flow:

H=kAdTdxH = -k A \frac{dT}{dx}

Here:

  • HH = heat flow rate (energy per unit time), so its dimensions are [Energy][Time]=ML2T2T=ML2T3\frac{[Energy]}{[Time]} = \frac{ML^2T^{-2}}{T} = ML^2T^{-3}.
  • AA = area, dimensions L2L^2.
  • dTdx\frac{dT}{dx} = temperature gradient, dimensions [Temperature][Length]=KL\frac{[Temperature]}{[Length]} = \frac{K}{L}.
Our goal is to isolate kk and find its dimensional formula.

Step-by-Step Derivation:

1. Start from Fourier’s law: H=kAdTdxH = -k A \frac{dT}{dx} 2. Rearrange to solve for kk: k=HAdTdxk = \frac{H}{A \frac{dT}{dx}} 3. Substitute the dimensions of each quantity:

  • HML2T3H \rightarrow ML^2T^{-3}
  • AL2A \rightarrow L^2
  • dTdxKL\frac{dT}{dx} \rightarrow \frac{K}{L}
4. Plug these into the expression for kk: [k]=ML2T3L2KL=ML2T3L2KL1=ML2T3L21K=ML2T3LK[k] = \frac{ML^2T^{-3}}{L^2 \cdot \frac{K}{L}} = \frac{ML^2T^{-3}}{L^2 \cdot K \cdot L^{-1}} = \frac{ML^2T^{-3}}{L^{2-1}K} = \frac{ML^2T^{-3}}{LK} 5. Simplify the powers of LL: [k]=ML21T3K1=MLT3K1[k] = ML^{2-1}T^{-3}K^{-1} = MLT^{-3}K^{-1} 6. Compare with the given options. The dimensional formula MLT3K1MLT^{-3}K^{-1} matches option A.

Common Traps & Exam Tip:

  • Confusing temperature gradient with temperature: Students often forget that dTdx\frac{dT}{dx} has dimensions KL\frac{K}{L}, not just KK. This leads to incorrect cancellation of KK and wrong options like MLT3KMLT^{-3}K.
  • Sign error in Fourier’s law: The negative sign in H=kAdTdxH = -k A \frac{dT}{dx} is purely conventional and does not affect dimensions. Ignore it during dimensional analysis.
  • Miscounting powers of LL: A frequent arithmetic mistake is miscounting LL exponents when dividing L2L^2 by L1L^{-1}. Double-check each step to avoid this.
  • Exam Tip: Always write down the dimensions of every physical quantity involved before substituting. This systematic approach minimizes errors and ensures clarity.

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