JEE PYQ: Motion in a Straight Line - Question ID b5b1c738e48a (JEE Main 2021)

Select Option
Step-by-step Explanation
When a particle moves with constant acceleration along a straight line, its motion is governed by three fundamental kinematic relations:
1. Position as a function of time: This is a quadratic function of time, so its graph is a parabola. 2. Velocity as a function of time: This is a linear function of time, so its graph is a straight line with slope equal to the constant acceleration \(a\). 3. Acceleration as a function of time: Since the acceleration is constant, its graph is a horizontal straight line.The question asks which set of three graphs (position, velocity, acceleration) correctly represents these shapes for motion with constant acceleration.
Step-by-Step Derivation:Step 1: Identify the expected shapes
- Position vs time: parabola (quadratic in \(t\)).
- Velocity vs time: straight line (linear in \(t\)).
- Acceleration vs time: horizontal line (constant).
Step 2: Examine each option
Option A
- Position graph: straight line (linear) ⇒ incorrect (should be parabolic).
- Velocity graph: straight line ⇒ correct.
- Acceleration graph: horizontal line ⇒ correct.
Since the position graph is wrong, Option A is invalid.
Option B
- Position graph: parabola (quadratic) ⇒ correct.
- Velocity graph: straight line ⇒ correct.
- Acceleration graph: horizontal line ⇒ correct.
All three graphs match the expected shapes. Option B is valid.
Option C
- Position graph: parabola ⇒ correct.
- Velocity graph: parabola ⇒ incorrect (should be linear).
- Acceleration graph: horizontal line ⇒ correct.
The velocity graph is wrong, so Option C is invalid.
Option D
- Position graph: parabola ⇒ correct.
- Velocity graph: straight line ⇒ correct.
- Acceleration graph: straight line with positive slope ⇒ incorrect (acceleration must be constant, hence horizontal).
The acceleration graph is wrong, so Option D is invalid.
Conclusion
Only Option B satisfies all three kinematic graphs for motion with constant acceleration.
1. Confusing position and velocity graphs: Many students mistake the parabolic position graph for the velocity graph. Remember: velocity is linear, position is quadratic. 2. Acceleration graph slope: A sloped acceleration graph implies changing acceleration, which contradicts the “constant acceleration” condition. 3. Graph concavity: The parabola for position must open upwards if acceleration is positive, and downwards if negative. Ensure the concavity matches the sign of \(a\).
Exam Tip: Always sketch the three graphs mentally before looking at the options. This quick check can save precious time.
Related Questions from Motion in a Straight Line
A gas balloon is going up with a constant velocity of . When this balloon reached a height of 75 m , a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is m. (Take )
The velocity versus time plot of a particle is shown in the figure, for a time interval of 40 s . The total distance travelled by the particle and the average velocity during this period are, respectively
.

Two cars and are moving in the same direction along a straight line with speeds and , respectively such that car is moving ahead of car . A person in car throws a stone with a speed so that it hits the car with a speed of . The value of is .
A particle starts moving from time and its coordinate is given as
A. The particle returns to its original position (origin) 0.866 units later
B. The particle is 1 unit away from origin at its turning point
C. Acceleration of the particle is non-negative
D. The particle is 0.5 units away from origin at its turning point
E. Particle never turns back as acceleration is non-negative
Choose the correct answer from the options given below :