JEE PYQ: Units & Measurements - Question ID 9c724138783c (JEE Main 2025)

ID: 9c724138783cJEE Main 2025Single Correct MCQ

A person measures mass of 3 different particles as 435.42 g,226.3 g435.42 \mathrm{~g}, 226.3 \mathrm{~g} and 0.125 g . According to the rules for arithmetic operations with significant figures, the addition of the masses of 3 particles will be.

Select Option

Step-by-step Explanation

Core Formula & Concept:

In the chapter Units & Measurements, one of the key concepts is the rule for arithmetic operations with significant figures. When adding or subtracting measured quantities, the result must be reported with the same number of decimal places as the measurement with the fewest decimal places. This ensures that the precision of the result is not overstated.

Given three masses:

  • m1=435.42 gm_1 = 435.42 \text{ g} (2 decimal places)
  • m2=226.3 gm_2 = 226.3 \text{ g} (1 decimal place)
  • m3=0.125 gm_3 = 0.125 \text{ g} (3 decimal places)

The sum must be rounded to the least number of decimal places among the three, which is 1 decimal place (from m2m_2).

Step-by-Step Derivation:

Step 1: Align the numbers by decimal place
Write all masses with the same number of decimal places for clarity:

  • 435.420 g435.420 \text{ g}
  • 226.300 g226.300 \text{ g}
  • 0.125 g0.125 \text{ g}

Step 2: Perform the addition
Add the masses directly: 435.420+226.300+0.125=661.845 g435.420 + 226.300 + 0.125 = 661.845 \text{ g}

Step 3: Apply the significant figures rule for addition
The measurement with the fewest decimal places is 226.3 g226.3 \text{ g} (1 decimal place). Thus, the result must be rounded to 1 decimal place.
Rounding 661.845661.845 to 1 decimal place:

  • The digit in the first decimal place is 8.
  • The digit in the second decimal place is 4, which is less than 5, so we do not round up the first decimal digit.
Thus, the rounded result is 661.8 g661.8 \text{ g}.

Step 4: Match with the given options
The correct answer is Option D: 661.8 g661.8 \text{ g}.

Common Traps & Exam Tip:

Trap 1: Ignoring the rule for addition/subtraction
Students often apply the multiplication/division rule (counting significant figures) instead of the addition/subtraction rule (counting decimal places). This leads to incorrect rounding.

Trap 2: Overlooking the least precise measurement
Some students mistakenly round based on the measurement with the most decimal places (e.g., 0.125 g0.125 \text{ g}) instead of the fewest (226.3 g226.3 \text{ g}).

Exam Tip:
Always align the numbers by decimal place before adding or subtracting. This makes it easier to identify the measurement with the fewest decimal places and apply the rounding rule correctly.

Related Questions from Units & Measurements

ID: 32f827e3012fJEE Main 2026

In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and 7th 7^{\text {th }} Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm and there are 10 Vernier scale divisions, then the Vernier caliper has

View Solution →
ID: 4c5472dca7e2JEE Main 2026

Dimensions of universal gravitational constant (GG) in terms of Planck's constant (hh), distance (LL), mass (MM) and time (TT) are _______.

View Solution →
ID: 605eaee8ed80JEE Main 2026

The time period of a simple harmonic oscillator is T=2πkmT = 2\pi \sqrt{\frac{k}{m}}. Measured value of mass (m)(m) of the object is 10 g with an accuracy of 10 mg and time for 50 oscillations of the spring is found to be 60 s using a watch of 2 s resolution. Percentage error in determination of spring constant (k)(k) is ________%.

View Solution →
ID: 5561befb0f22JEE Main 2026

When both jaws of vernier callipers touch each other, zero mark of the vernier scale is right to zero mark of main scale, 4th 4{ }^{\text {th }} mark on vernier scale coincides with certain mark on the main scale. While measuring the length of a cylinder, observer observes 15 divisions on main scale and 5th 5^{\text {th }} division of vernier scale coincides with a main scale division. Measured length of cylinder is ____\_\_\_\_ mm.

(Least count of Vernier calliper =0.1 mm=0.1 \mathrm{~mm} )

View Solution →