JEE PYQ: Units & Measurements - Question ID 9c70f74daf46 (JEE Main 2024)

ID: 9c70f74daf46JEE Main 2024Single Correct MCQ

Consider two physical quantities AA and BB related to each other as E=Bx2AtE=\frac{B-x^2}{A t} where E,xE, x and tt have dimensions of energy, length and time respectively. The dimension of ABA B is

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Step-by-step Explanation

[B]=L2 A=x2tE=L2TML2 T2=1MT1[ A]=M1 T[AB]=[L2M1 T1]\begin{aligned} & {[\mathrm{B}]=\mathrm{L}^2} \\ & \mathrm{~A}=\frac{\mathrm{x}^2}{\mathrm{tE}}=\frac{\mathrm{L}^2}{\mathrm{TML}^2 \mathrm{~T}^{-2}}=\frac{1}{\mathrm{MT}^{-1}} \\ & {[\mathrm{~A}]=\mathrm{M}^{-1 \mathrm{~T}}} \\ & {[\mathrm{AB}]=\left[\mathrm{L}^2 \mathrm{M}^{-1} \mathrm{~T}^1\right]} \end{aligned}

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