JEE PYQ: Units & Measurements - Question ID 7a2aaadd2a71 (JEE Main 2021)

ID: 7a2aaadd2a71JEE Main 2021Single Correct MCQ
Match List - I with List - II

List-IList-II
(a)Magnetic Induction(i)ML2T-2A-1
(b)Magnetic Flux(ii)M0L-1A
(c)Magnetic Permeability(iii)MT-2A-1
(d)Magnetization(iv)MLT-2A-2

Choose the most appropriate answer from the options given below :

Select Option

Step-by-step Explanation

Core Formula & Concept:

In the SI system, every physical quantity can be expressed in terms of four fundamental dimensions: mass (MM), length (LL), time (TT), and electric current (AA). The key formulas we use are:

  • Magnetic induction (B): From the Lorentz force F=q(v×B)\vec{F} = q(\vec{v} \times \vec{B}), we get [B]=[F][q][v]=MLT2(AT)(LT1)=MT2A1[B] = \frac{[F]}{[q][v]} = \frac{MLT^{-2}}{(AT)(LT^{-1})} = MT^{-2}A^{-1}.
  • Magnetic flux (Φ): Φ=BA\Phi = \vec{B} \cdot \vec{A} gives [Φ]=[B][A]=(MT2A1)(L2)=ML2T2A1[\Phi] = [B][A] = (MT^{-2}A^{-1})(L^{2}) = ML^{2}T^{-2}A^{-1}.
  • Magnetic permeability (μ): From B=μHB = \mu H and knowing [H]=L1A[H] = L^{-1}A, we obtain [μ]=[B][H]=MT2A1L1A=MLT2A2[\mu] = \frac{[B]}{[H]} = \frac{MT^{-2}A^{-1}}{L^{-1}A} = MLT^{-2}A^{-2}.
  • Magnetization (M): Magnetization is magnetic moment per unit volume, so [M]=[m][V]=AL2L3=L1A[M] = \frac{[m]}{[V]} = \frac{AL^{2}}{L^{3}} = L^{-1}A.
Step-by-Step Derivation:

Step 1: Magnetic Induction (B)

From F=q(v×B)\vec{F} = q(\vec{v} \times \vec{B}) we isolate BB: [B]=[F][q][v]=MLT2(AT)(LT1)=MT2A1[B] = \frac{[F]}{[q][v]} = \frac{MLT^{-2}}{(AT)(LT^{-1})} = MT^{-2}A^{-1}. This matches List-II entry (iii).

Step 2: Magnetic Flux (Φ)

Φ=BA\Phi = B \cdot A gives [Φ]=[B][A]=(MT2A1)(L2)=ML2T2A1[\Phi] = [B][A] = (MT^{-2}A^{-1})(L^{2}) = ML^{2}T^{-2}A^{-1}. This matches List-II entry (i).

Step 3: Magnetic Permeability (μ)

B=μHB = \mu H and [H]=L1A[H] = L^{-1}A lead to [μ]=[B][H]=MT2A1L1A=MLT2A2[\mu] = \frac{[B]}{[H]} = \frac{MT^{-2}A^{-1}}{L^{-1}A} = MLT^{-2}A^{-2}. This matches List-II entry (iv).

Step 4: Magnetization (M)

Magnetization is magnetic moment per unit volume: [M]=[m][V]=AL2L3=L1A[M] = \frac{[m]}{[V]} = \frac{AL^{2}}{L^{3}} = L^{-1}A. This matches List-II entry (ii).

Step 5: Matching to Options

We have: (a) → (iii), (b) → (i), (c) → (iv), (d) → (ii). This corresponds exactly to option D.

Common Traps & Exam Tip:

Students often confuse the dimensions of magnetic induction (BB) with those of magnetic flux (Φ\Phi), swapping (iii) and (i). Another frequent error is misidentifying magnetization as having the same dimensions as magnetic field strength (HH), leading to an incorrect match for (d). Always derive each dimension from first principles rather than relying on memory.

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