JEE PYQ: Units & Measurements - Question ID 715bcd91c9e2 (JEE Main 2026)

ID: 715bcd91c9e2JEE Main 2026Single Correct MCQ

 Match the LIST-I with LIST-II \text { Match the LIST-I with LIST-II }

List - I
List - II
A. Planck's constant I. <br>ML2 T2<br><br>\mathrm{ML}^2 \mathrm{~T}^{-2}<br>
B. Stopping potential II. <br>T1<br><br>\mathrm{T}^{-1}<br>
C. Work function III. <br>ML2 T1<br><br>\mathrm{ML}^2 \mathrm{~T}^{-1}<br>
D. Threshold frequency IV. <br>ML2 T3 A1<br><br>\mathrm{ML}^2 \mathrm{~T}^{-3} \mathrm{~A}^{-1}<br>

Choose the correct answer from the options given below:

Select Option

Step-by-step Explanation

Core Formula & Concept:

In dimensional analysis, every physical quantity can be expressed in terms of the fundamental dimensions: mass (M\mathrm{M}), length (L\mathrm{L}), time (T\mathrm{T}), electric current (A\mathrm{A}), etc. The question requires us to match four physical quantities (Planck’s constant, stopping potential, work function, and threshold frequency) with their correct dimensional formulae from List-II.

Key formulas and their dimensions:

  • Planck’s constant (hh): From the relation E=hνE = h \nu, where EE is energy and ν\nu is frequency, we get h=Eνh = \frac{E}{\nu}. The dimensions of energy are ML2T2\mathrm{ML}^2 \mathrm{T}^{-2} and frequency is T1\mathrm{T}^{-1}, so hh has dimensions ML2T2T1=ML2T1\frac{\mathrm{ML}^2 \mathrm{T}^{-2}}{\mathrm{T}^{-1}} = \mathrm{ML}^2 \mathrm{T}^{-1}.
  • Stopping potential (V0V_0): This is an electric potential, defined as the work done per unit charge. The dimensions of work are ML2T2\mathrm{ML}^2 \mathrm{T}^{-2} and charge is IT\mathrm{IT}, so potential has dimensions ML2T2IT=ML2T3A1\frac{\mathrm{ML}^2 \mathrm{T}^{-2}}{\mathrm{IT}} = \mathrm{ML}^2 \mathrm{T}^{-3} \mathrm{A}^{-1}.
  • Work function (ϕ\phi): This is the minimum energy required to eject an electron from a metal surface. Energy has dimensions ML2T2\mathrm{ML}^2 \mathrm{T}^{-2}.
  • Threshold frequency (ν0\nu_0): This is the minimum frequency of light required to eject an electron. Frequency has dimensions T1\mathrm{T}^{-1}.
Step-by-Step Derivation:
  1. Planck’s constant (A): From E=hνE = h \nu, we derive: h=Eν    [h]=ML2T2T1=ML2T1h = \frac{E}{\nu} \implies [h] = \frac{\mathrm{ML}^2 \mathrm{T}^{-2}}{\mathrm{T}^{-1}} = \mathrm{ML}^2 \mathrm{T}^{-1}. This matches III in List-II.

  2. Stopping potential (B): Stopping potential is an electric potential, given by V0=WqV_0 = \frac{W}{q}, where WW is work and qq is charge. The dimensions are: [V0]=ML2T2IT=ML2T3A1[V_0] = \frac{\mathrm{ML}^2 \mathrm{T}^{-2}}{\mathrm{IT}} = \mathrm{ML}^2 \mathrm{T}^{-3} \mathrm{A}^{-1}. This matches IV in List-II.

  3. Work function (C): The work function is energy, so its dimensions are: [ϕ]=ML2T2[\phi] = \mathrm{ML}^2 \mathrm{T}^{-2}. This matches I in List-II.

  4. Threshold frequency (D): Frequency has dimensions: [ν0]=T1[\nu_0] = \mathrm{T}^{-1}. This matches II in List-II.

Thus, the correct matching is: A-III, B-IV, C-I, D-II, which corresponds to Option A.

Common Traps & Exam Tip:

Students often confuse the dimensions of stopping potential with those of electric field or resistance. Remember:

  • Stopping potential is a potential (work per unit charge), not an electric field (force per unit charge).
  • Planck’s constant is not energy; it is energy per unit frequency.
  • Work function is energy, not power (which has dimensions ML2T3\mathrm{ML}^2 \mathrm{T}^{-3}).
  • Threshold frequency is a frequency, not angular frequency (which has dimensions T1\mathrm{T}^{-1} but is often mistakenly associated with T2\mathrm{T}^{-2}).
Always derive dimensions from first principles to avoid such mistakes.

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