JEE PYQ: Units & Measurements - Question ID 5f6fccef78b7 (JEE Main 2026)
In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5 mm . If the circular scale has 100 divisions, the least count of screw gauge is mm.
Select Option
Step-by-step Explanation
In a screw gauge (also called a micrometer screw), two scales work together:
- The main scale (linear scale) is marked along the sleeve.
- The circular scale (thimble scale) is marked on the rotating thimble.
The pitch of the screw is the linear distance moved by the screw per complete rotation of the thimble. The least count (LC) is the smallest distance that can be measured with the instrument. It is given by:
Step-by-Step Derivation:Step 1: Determine the pitch of the screw.
The question states that when the circular scale is given five complete rotations, it moves linearly by 2.5 mm. Therefore, the linear distance moved per complete rotation (pitch) is:
Step 2: Use the number of divisions on the circular scale.
The circular scale has 100 divisions. The least count is the pitch divided by the number of divisions on the circular scale:
Step 3: Express the least count in scientific notation.
.
This matches option D.
Common Traps & Exam Tip:Trap 1: Students often confuse the total linear movement with the pitch. They might directly divide 2.5 mm by 100 divisions, skipping the pitch calculation. This leads to an incorrect least count of mm.
Trap 2: Misinterpreting the number of rotations. If a student mistakenly takes 1 rotation instead of 5, the pitch becomes 2.5 mm, leading to a least count of mm.
Exam Tip: Always calculate the pitch first by dividing the total linear movement by the number of complete rotations. Then, divide the pitch by the number of circular scale divisions to find the least count.
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