JEE PYQ: Vector Algebra - Question ID 5db0c1b33026 (JEE Main 2023)

ID: 5db0c1b33026JEE Main 2023Single Correct MCQ

If two vectors P=i^+2mj^+mk^\overrightarrow P = \widehat i + 2m\widehat j + m\widehat k and Q=4i^2j^+mk^\overrightarrow Q = 4\widehat i - 2\widehat j + m\widehat k are perpendicular to each other. Then, the value of m will be :

Select Option

Step-by-step Explanation

Core Formula & Concept:

In vector algebra, two vectors are said to be perpendicular (or orthogonal) if and only if their dot product is zero. The dot product of two vectors \(\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k}\) and \(\vec{B} = B_x \hat{i} + B_y \hat{j} + B_z \hat{k}\) is defined as: AB=AxBx+AyBy+AzBz\vec{A} \cdot \vec{B} = A_x B_x + A_y B_y + A_z B_z If \(\vec{A} \cdot \vec{B} = 0\), then \(\vec{A}\) and \(\vec{B}\) are perpendicular.

In this problem, we are given two vectors \(\vec{P}\) and \(\vec{Q}\) and told they are perpendicular. We will use the dot product condition to find the value of \(m\).

Step-by-Step Derivation:

Given vectors: P=i^+2mj^+mk^\vec{P} = \hat{i} + 2m \hat{j} + m \hat{k} Q=4i^2j^+mk^\vec{Q} = 4 \hat{i} - 2 \hat{j} + m \hat{k}

Since \(\vec{P}\) and \(\vec{Q}\) are perpendicular: PQ=0\vec{P} \cdot \vec{Q} = 0

Compute the dot product: PQ=(1)(4)+(2m)(2)+(m)(m)=0\vec{P} \cdot \vec{Q} = (1)(4) + (2m)(-2) + (m)(m) = 0 Simplify: 44m+m2=04 - 4m + m^2 = 0

Rearrange the equation: m24m+4=0m^2 - 4m + 4 = 0 This is a quadratic equation in \(m\).

Solve the quadratic equation: m=4±(4)24142=4±16162=4±02=2m = \frac{4 \pm \sqrt{(-4)^2 - 4 \cdot 1 \cdot 4}}{2} = \frac{4 \pm \sqrt{16 - 16}}{2} = \frac{4 \pm 0}{2} = 2 Thus, \(m = 2\).

The value of \(m\) that satisfies the condition is \(2\), which corresponds to option D.

Common Traps & Exam Tip:

1. Sign Errors in Dot Product: Students often make mistakes in the sign while computing the dot product, especially when dealing with negative components. For example, in this problem, the \(j\)-component of \(\vec{Q}\) is \(-2\), and multiplying it with \(2m\) gives \(-4m\), not \(+4m\).

2. Forgetting the Dot Product Condition: Some students confuse the condition for perpendicular vectors with that for parallel vectors. Remember: perpendicular vectors have a dot product of zero, while parallel vectors are scalar multiples of each other.

3. Quadratic Equation Mistakes: While solving the quadratic equation, students may incorrectly compute the discriminant or misapply the quadratic formula. Always double-check the discriminant calculation.

Exam Tip: When solving such problems, always write down the dot product explicitly and verify each term before simplifying. This minimizes errors and ensures accuracy.