JEE PYQ: Units & Measurements - Question ID 4ce272101871 (JEE Main 2024)
While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is and circular scale reading is equal to 42 divisions. Pitch of screw gauge is and it has 100 divisions on circular scale. The diameter of the wire is . The value of is :
Select Option
Step-by-step Explanation
When measuring small lengths (like the diameter of a wire) with a screw gauge, two scales work together:
- The main scale (linear scale) gives a coarse reading in whole millimeters.
- The circular scale (rotating thimble) subdivides each millimeter into finer parts.
The pitch of the screw gauge is the distance the spindle advances along the main scale when the circular scale makes one complete revolution. Here, the pitch is and the circular scale has divisions. Therefore, the least count (smallest measurable length) is:
The total measured diameter is the sum of the main scale reading and the circular scale reading multiplied by the least count:
Step-by-Step Derivation:Given:
- Main scale reading =
- Circular scale reading = divisions
- Pitch =
- Number of divisions on circular scale =
Step 1: Calculate the least count.
Step 2: Compute the circular scale contribution.
Step 3: Add the main scale reading to get the total diameter.
Step 4: Express the diameter in the form . Multiply both sides by :
Common Traps & Exam Tip:Students often confuse the pitch with the least count. They might directly multiply the circular scale reading by the pitch (e.g., ), which is incorrect. Always remember:
- The pitch is the distance per full revolution.
- The least count is the pitch divided by the number of circular scale divisions.
- The circular scale reading must be multiplied by the least count, not the pitch.
Another common mistake is miscounting the number of divisions or misinterpreting the main scale reading. Double-check the given values before performing calculations.
Related Questions from Units & Measurements
In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm and there are 10 Vernier scale divisions, then the Vernier caliper has
Dimensions of universal gravitational constant () in terms of Planck's constant (), distance (), mass () and time () are _______.
The time period of a simple harmonic oscillator is . Measured value of mass of the object is 10 g with an accuracy of 10 mg and time for 50 oscillations of the spring is found to be 60 s using a watch of 2 s resolution. Percentage error in determination of spring constant is ________%.
When both jaws of vernier callipers touch each other, zero mark of the vernier scale is right to zero mark of main scale, mark on vernier scale coincides with certain mark on the main scale. While measuring the length of a cylinder, observer observes 15 divisions on main scale and division of vernier scale coincides with a main scale division. Measured length of cylinder is mm.
(Least count of Vernier calliper )