JEE PYQ: Units & Measurements - Question ID 4bb097bd6a85 (JEE Main 2008)

ID: 4bb097bd6a85JEE Main 2008Single Correct MCQ
The dimension of magnetic field in M, L, T and C (coulomb) is given as

Select Option

Step-by-step Explanation

Core Formula & Concept:

To determine the dimensional formula of the magnetic field (BB), we rely on the fundamental force law that connects electricity and magnetism: the Lorentz force. The Lorentz force on a charge qq moving with velocity v\vec{v} in a magnetic field B\vec{B} is given by: F=q(v×B)\vec{F} = q \left( \vec{v} \times \vec{B} \right) From this, we can isolate the magnetic field BB and express it in terms of the dimensions of force (FF), charge (qq), and velocity (vv).

Step-by-Step Derivation:

Step 1: Express the magnitude of the Lorentz force.
The magnitude of the Lorentz force is: F=qvBsinθF = q v B \sin \theta Since sinθ\sin \theta is dimensionless, we can ignore it for dimensional analysis. Thus: F=qvBF = q v B

Step 2: Solve for the magnetic field BB.
Rearranging the equation to solve for BB: B=FqvB = \frac{F}{q v}

Step 3: Substitute the dimensions of each quantity.
We know the dimensions of the quantities involved:

  • Force (FF): MLT2MLT^{-2}
  • Charge (qq): CC (Coulomb)
  • Velocity (vv): LT1LT^{-1}
Substituting these into the equation for BB: B=MLT2CLT1B = \frac{MLT^{-2}}{C \cdot LT^{-1}}

Step 4: Simplify the dimensions.
Simplify the expression by canceling out common terms: B=MLT2CLT1=MCLLT2T1=MT1C1B = \frac{MLT^{-2}}{C L T^{-1}} = \frac{M}{C} \cdot \frac{L}{L} \cdot \frac{T^{-2}}{T^{-1}} = M T^{-1} C^{-1} Thus, the dimensional formula of the magnetic field is: [B]=MT1C1[B] = MT^{-1}C^{-1}

Step 5: Match with the given options.
Comparing the derived dimension MT1C1MT^{-1}C^{-1} with the options:

  • A: MLT1C1MLT^{-1}C^{-1} → Incorrect (extra LL)
  • B: MT2C2MT^{2}C^{-2} → Incorrect (wrong powers of TT and CC)
  • C: MT1C1MT^{-1}C^{-1} → Correct
  • D: MT2C1MT^{-2}C^{-1} → Incorrect (wrong power of TT)

Common Traps & Exam Tip:

Students often make the following mistakes in this question:

  1. Confusing magnetic field with magnetic flux: The magnetic flux (ΦB\Phi_B) has dimensions ML2T2C1ML^2T^{-2}C^{-1}, which is different from the magnetic field. Students sometimes mix these up.
  2. Incorrectly applying the Lorentz force formula: Some forget that the force depends on the cross product of velocity and magnetic field, leading to incorrect dimensional cancellations.
  3. Miscounting powers of LL: In the simplification step, students may incorrectly cancel LL or retain it, leading to options like A (which includes an extra LL).
  4. Misremembering the unit of charge: Some students use AA (Ampere) instead of CC (Coulomb) for charge, which complicates the dimensional analysis unnecessarily.
Exam Tip: Always start from the fundamental force law (Lorentz force) when deriving dimensions for magnetic field. Double-check each step for dimensional consistency, especially the powers of LL, TT, and CC.

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