JEE PYQ: Motion in a Straight Line - Question ID 4a58e7cbaca6 (JEE Main 2022)

ID: 4a58e7cbaca6JEE Main 2022Numerical Value

A car covers AB distance with first one-third at velocity v1 ms-1, second one-third at v2 ms-1 and last one-third at v3 ms-1. If v3 = 3v1, v2 = 2v1 and v1 = 11 ms-1 then the average velocity of the car is _____________ ms-1.

JEE Main 2022 (Online) 28th June Evening Shift Physics - Motion in a Straight Line Question 65 English

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Step-by-step Explanation

Core Formula & Concept:

In straight-line motion, the average velocity over a journey is defined as the total displacement divided by the total time taken. Mathematically, Average velocity=Total displacementTotal time.\text{Average velocity} = \frac{\text{Total displacement}}{\text{Total time}}. When the path is straight and the motion is along the same line, displacement equals the distance travelled, so we may write Average velocity=Total distanceTotal time.\text{Average velocity} = \frac{\text{Total distance}}{\text{Total time}}.

If the journey is split into segments of equal length, each segment’s time is ti=Segment distancevi.t_i = \frac{\text{Segment distance}}{v_i}. Summing these times gives the total time.

Step-by-Step Derivation:

Given data:

  • Total distance AB = DD.
  • First one-third: v1=11 ms1v_1 = 11\ \text{ms}^{-1}.
  • Second one-third: v2=2v1=22 ms1v_2 = 2v_1 = 22\ \text{ms}^{-1}.
  • Last one-third: v3=3v1=33 ms1v_3 = 3v_1 = 33\ \text{ms}^{-1}.

Step 1: Express each segment’s distance.
Each segment is one-third of the total distance: d1=d2=d3=D3.d_1 = d_2 = d_3 = \frac{D}{3}.

Step 2: Compute the time for each segment.
t1=d1v1=D/311=D33,t_1 = \frac{d_1}{v_1} = \frac{D/3}{11} = \frac{D}{33}, t2=d2v2=D/322=D66,t_2 = \frac{d_2}{v_2} = \frac{D/3}{22} = \frac{D}{66}, t3=d3v3=D/333=D99.t_3 = \frac{d_3}{v_3} = \frac{D/3}{33} = \frac{D}{99}.

Step 3: Sum the times to get the total time.
T=t1+t2+t3=D33+D66+D99.T = t_1 + t_2 + t_3 = \frac{D}{33} + \frac{D}{66} + \frac{D}{99}. To add these fractions, find a common denominator. The least common multiple of 33, 66, and 99 is 198. T=6D198+3D198+2D198=11D198=D18.T = \frac{6D}{198} + \frac{3D}{198} + \frac{2D}{198} = \frac{11D}{198} = \frac{D}{18}.

Step 4: Compute the average velocity.
Average velocity=Total distanceTotal time=DD/18=18 ms1.\text{Average velocity} = \frac{\text{Total distance}}{\text{Total time}} = \frac{D}{D/18} = 18\ \text{ms}^{-1}. Common Traps & Exam Tip:

1. Mistaking average speed for average velocity: Some students compute the arithmetic mean of the speeds v1+v2+v33\tfrac{v_1+v_2+v_3}{3}, which is incorrect because the times spent at each speed differ. 2. Incorrect fraction addition: A frequent arithmetic error is failing to find a common denominator when summing the segment times. 3. Ignoring the equal-distance split: One must remember that each segment is exactly one-third of the total distance, not arbitrary lengths.

Exam tip: Always write down the definition of average velocity first, then break the journey into segments, compute each time, sum them, and finally divide total distance by total time.

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