JEE PYQ: Units & Measurements - Question ID 466a53d0a4c8 (JEE Main 2024)

ID: 466a53d0a4c8JEE Main 2024Single Correct MCQ

What is the dimensional formula of ab1a b^{-1} in the equation (P+aV2)(Vb)=RT\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}, where letters have their usual meaning.

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Step-by-step Explanation

Core Formula & Concept:

The given equation is the van der Waals equation of state for real gases: (P+aV2)(Vb)=RT.\left(P + \frac{a}{V^2}\right)(V - b) = RT. Here:

  • PP is pressure,
  • VV is molar volume,
  • TT is absolute temperature,
  • RR is the universal gas constant,
  • aa and bb are van der Waals constants that correct for intermolecular forces and finite molecular size, respectively.

Dimensional homogeneity principle: Every additive term in a physically meaningful equation must have the same dimensions. We exploit this to find the dimensions of aa and bb.

Step-by-Step Derivation:

Step 1: Dimensions of known quantities

  • Pressure PP: [P]=ML1T2[P] = \mathrm{ML}^{-1}\mathrm{T}^{-2}
  • Volume VV: [V]=L3[V] = \mathrm{L}^{3}
  • Temperature TT: [T]=Θ[T] = \mathrm{\Theta}
  • Gas constant RR: [R]=ML2T2Θ1[R] = \mathrm{ML}^{2}\mathrm{T}^{-2}\mathrm{\Theta}^{-1}

Step 2: Isolate the term containing aa
The term aV2\displaystyle \frac{a}{V^2} must have the same dimensions as PP (since they are added): [aV2]=[P].\left[\frac{a}{V^2}\right] = [P]. Therefore [a]=[P][V2]=ML1T2(L3)2=ML5T2.[a] = [P] \cdot [V^2] = \mathrm{ML}^{-1}\mathrm{T}^{-2} \cdot (\mathrm{L}^{3})^{2} = \mathrm{ML}^{5}\mathrm{T}^{-2}.

Step 3: Dimensions of bb
The term bb is subtracted from VV, so [b]=[V]=L3.[b] = [V] = \mathrm{L}^{3}.

Step 4: Dimensions of ab1a b^{-1}
We now compute [ab1]=[a][b]=ML5T2L3=ML2T2.\left[a b^{-1}\right] = \frac{[a]}{[b]} = \frac{\mathrm{ML}^{5}\mathrm{T}^{-2}}{\mathrm{L}^{3}} = \mathrm{ML}^{2}\mathrm{T}^{-2}.

Step 5: Match with the given options
The dimensional formula ML2T2\mathrm{ML}^{2}\mathrm{T}^{-2} corresponds exactly to option D.

Common Traps & Exam Tip:

  1. Confusing aa and bb roles: Students sometimes mix up which constant corrects for volume and which for pressure. Remember aa is associated with the pressure correction aV2\displaystyle \frac{a}{V^2}, while bb is the excluded volume.
  2. Incorrect exponent on VV: A frequent error is writing [V2]=L6[V^2] = \mathrm{L}^{6} instead of L6\mathrm{L}^{6} (correct), leading to wrong dimensions for aa.
  3. Forgetting to invert bb: The question asks for ab1a b^{-1}, not aa or bb alone. Always read the question carefully.

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