JEE PYQ: Units & Measurements - Question ID 4238a25f4cbe (JEE Main 2012)

ID: 4238a25f4cbeJEE Main 2012Single Correct MCQ
Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is

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Step-by-step Explanation

Core Formula & Concept:

In physics, resistance RR of a conductor is defined by Ohm’s law as the ratio of the voltage difference VV applied across it to the current II flowing through it: R=VI.R = \frac{V}{I}. When both VV and II are measured experimentally, their uncertainties propagate into the calculated resistance. The key concept here is error propagation in division. If two quantities xx and yy have percentage errors δx\delta x and δy\delta y, then the percentage error in their ratio xy\frac{x}{y} is the sum of the individual percentage errors: δ(xy)=δx+δy.\delta\left(\frac{x}{y}\right) = \delta x + \delta y. This rule arises from the logarithmic differentiation of the ratio.

Step-by-Step Derivation:

Step 1: Express the resistance formula
We start with Ohm’s law: R=VI.R = \frac{V}{I}.

Step 2: Take natural logarithm on both sides
To handle percentage errors, we take the natural logarithm: lnR=lnVlnI.\ln R = \ln V - \ln I.

Step 3: Differentiate both sides
Differentiating with respect to the measured quantities gives: dRR=dVVdII.\frac{dR}{R} = \frac{dV}{V} - \frac{dI}{I}.

Step 4: Convert differentials to percentage errors
The differentials dVV\frac{dV}{V} and dII\frac{dI}{I} represent the relative errors in VV and II. Converting these to percentage errors (multiplying by 100) yields: δR=δV+δI,\delta R = \delta V + \delta I, where δR\delta R, δV\delta V, and δI\delta I are the percentage errors in RR, VV, and II respectively.

Step 5: Substitute the given percentage errors
The question states that the percentage errors in current and voltage are each 3 %. Hence: δV=3%,δI=3%.\delta V = 3\%,\quad \delta I = 3\%. Substituting into the error propagation formula: δR=3%+3%=6%.\delta R = 3\% + 3\% = 6\%.

Step 6: Match with the given options
The calculated percentage error in resistance is 6 %, which corresponds to option A.

Common Traps & Exam Tip:

A frequent mistake students make is to average the percentage errors or to assume that errors cancel out in division. Some even think the error in resistance is simply the larger of the two errors (3 %). However, the correct rule for division is that percentage errors add. Always remember: δ(xy)=δx+δy.\delta\left(\frac{x}{y}\right) = \delta x + \delta y.

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