JEE PYQ: Motion in a Straight Line - Question ID 235a1db5d4ec (JEE Main 2023)

ID: 235a1db5d4ecJEE Main 2023Single Correct MCQ

A person travels xx distance with velocity v1v_{1} and then xx distance with velocity v2v_{2} in the same direction. The average velocity of the person is v\mathrm{v}, then the relation between v,v1v, v_{1} and v2v_{2} will be.

Select Option

Step-by-step Explanation

Core Formula & Concept:

In kinematics, the average velocity (VavgV_{\text{avg}}) over a journey is defined as the total displacement divided by the total time taken. Mathematically, Vavg=Total DisplacementTotal Time Taken.V_{\text{avg}} = \frac{\text{Total Displacement}}{\text{Total Time Taken}}.

When a person travels two equal distances (xx each) with different velocities (v1v_1 and v2v_2), the total displacement is 2x2x, but the total time taken is the sum of the individual times for each segment: t1=xv1,t2=xv2.t_1 = \frac{x}{v_1}, \quad t_2 = \frac{x}{v_2}. Thus, the average velocity VV is: V=2xt1+t2.V = \frac{2x}{t_1 + t_2}. This concept is crucial for solving problems involving non-uniform motion over equal distances.

Step-by-Step Derivation:

Let’s derive the relationship systematically:

  1. Define the journey segments:
    • First segment: Distance = xx, Velocity = v1v_1.
    • Second segment: Distance = xx, Velocity = v2v_2.
  2. Calculate time for each segment: t1=Distance1Velocity1=xv1,t2=xv2.t_1 = \frac{\text{Distance}_1}{\text{Velocity}_1} = \frac{x}{v_1}, \quad t_2 = \frac{x}{v_2}.
  3. Compute total displacement and total time:
    • Total displacement = x+x=2xx + x = 2x.
    • Total time = t1+t2=xv1+xv2t_1 + t_2 = \frac{x}{v_1} + \frac{x}{v_2}.
  4. Express average velocity (VV): V=Total DisplacementTotal Time=2xxv1+xv2.V = \frac{\text{Total Displacement}}{\text{Total Time}} = \frac{2x}{\frac{x}{v_1} + \frac{x}{v_2}}.
  5. Simplify the expression: Factor out xx from the denominator: V=2xx(1v1+1v2)=21v1+1v2.V = \frac{2x}{x \left( \frac{1}{v_1} + \frac{1}{v_2} \right)} = \frac{2}{\frac{1}{v_1} + \frac{1}{v_2}}.
  6. Rearrange to match the given options: Take the reciprocal of both sides: 1V=1v1+1v22    2V=1v1+1v2.\frac{1}{V} = \frac{\frac{1}{v_1} + \frac{1}{v_2}}{2} \implies \frac{2}{V} = \frac{1}{v_1} + \frac{1}{v_2}.

This matches Option D.

Common Traps & Exam Tip:

Students often confuse average velocity with average speed or assume arithmetic mean applies here. Key mistakes include:

  • Using arithmetic mean (Option B): Assuming V=v1+v22V = \frac{v_1 + v_2}{2} is incorrect because average velocity depends on time spent at each velocity, not just the velocities themselves.
  • Ignoring equal distances: If distances were unequal, the formula would differ. Here, equal distances simplify the problem.
  • Reciprocal confusion: Students may misapply the harmonic mean. Remember: For equal distances, average velocity is the harmonic mean of the two velocities.

Exam Tip: Always write down the definition of average velocity first. For equal distances, the formula 2V=1v1+1v2\frac{2}{V} = \frac{1}{v_1} + \frac{1}{v_2} is a direct consequence of the definition.

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