JEE PYQ: Units & Measurements - Question ID 1ef7854c8696 (JEE Main 2024)

ID: 1ef7854c8696JEE Main 2024Single Correct MCQ

If 50 Vernier divisions are equal to 49 main scale divisions of a traveling microscope and one smallest reading of main scale is 0.5 mm0.5 \mathrm{~mm}, the Vernier constant of traveling microscope is

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Step-by-step Explanation

Core Formula & Concept:

In a Vernier instrument (such as a traveling microscope), the Vernier constant (also called the least count) is the smallest length that can be measured accurately. It is defined as the difference between one main-scale division and one Vernier-scale division.

Key formula: Vernier constant=Value of one main-scale divisionValue of one Vernier-scale division\text{Vernier constant} = \text{Value of one main-scale division} - \text{Value of one Vernier-scale division}

If nn Vernier divisions coincide with (n1)(n-1) main-scale divisions, then: n×Vernier division=(n1)×Main-scale divisionn \times \text{Vernier division} = (n-1) \times \text{Main-scale division} Rearranging gives: Vernier division=(n1)n×Main-scale division\text{Vernier division} = \frac{(n-1)}{n} \times \text{Main-scale division} Hence, Vernier constant=Main-scale divisionVernier division=1n×Main-scale division\text{Vernier constant} = \text{Main-scale division} - \text{Vernier division} = \frac{1}{n} \times \text{Main-scale division}

Step-by-Step Derivation:

Given:

  • 50 Vernier divisions = 49 main-scale divisions
  • One main-scale division = 0.5 mm0.5 \text{ mm}

Step 1: Express the value of one Vernier division.
Since 50 Vernier divisions = 49 main-scale divisions, 50×Vernier division=49×Main-scale division50 \times \text{Vernier division} = 49 \times \text{Main-scale division} Vernier division=4950×Main-scale division\text{Vernier division} = \frac{49}{50} \times \text{Main-scale division}

Step 2: Substitute the value of one main-scale division.
Vernier division=4950×0.5 mm=4950×12 mm=49100 mm=0.49 mm\text{Vernier division} = \frac{49}{50} \times 0.5 \text{ mm} = \frac{49}{50} \times \frac{1}{2} \text{ mm} = \frac{49}{100} \text{ mm} = 0.49 \text{ mm}

Step 3: Calculate the Vernier constant.
Vernier constant=Main-scale divisionVernier division=0.5 mm0.49 mm=0.01 mm\text{Vernier constant} = \text{Main-scale division} - \text{Vernier division} = 0.5 \text{ mm} - 0.49 \text{ mm} = 0.01 \text{ mm}

Step 4: Match with the given options.
The Vernier constant is 0.01 mm0.01 \text{ mm}, which corresponds to option A.

Common Traps & Exam Tip:

  • Unit confusion: Students often mix up millimeters and centimeters. Always double-check the units in the question and options.
  • Incorrect formula application: Some students mistakenly use the formula Vernier constant=Main-scale divisionn\text{Vernier constant} = \frac{\text{Main-scale division}}{n} without understanding the underlying principle. Always derive it from first principles to avoid errors.
  • Misinterpretation of divisions: Ensure that the number of Vernier divisions and main-scale divisions are correctly matched (here, 50 Vernier divisions = 49 main-scale divisions).

Exam Tip: When solving Vernier constant problems, always write down the given data clearly and derive the value step-by-step. This minimizes errors and ensures full marks.

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