JEE PYQ: Units & Measurements - Question ID 1ef7854c8696 (JEE Main 2024)
If 50 Vernier divisions are equal to 49 main scale divisions of a traveling microscope and one smallest reading of main scale is , the Vernier constant of traveling microscope is
Select Option
Step-by-step Explanation
In a Vernier instrument (such as a traveling microscope), the Vernier constant (also called the least count) is the smallest length that can be measured accurately. It is defined as the difference between one main-scale division and one Vernier-scale division.
Key formula:
If Vernier divisions coincide with main-scale divisions, then: Rearranging gives: Hence,
Step-by-Step Derivation:Given:
- 50 Vernier divisions = 49 main-scale divisions
- One main-scale division =
Step 1: Express the value of one Vernier division.
Since 50 Vernier divisions = 49 main-scale divisions,
Step 2: Substitute the value of one main-scale division.
Step 3: Calculate the Vernier constant.
Step 4: Match with the given options.
The Vernier constant is , which corresponds to option A.
- Unit confusion: Students often mix up millimeters and centimeters. Always double-check the units in the question and options.
- Incorrect formula application: Some students mistakenly use the formula without understanding the underlying principle. Always derive it from first principles to avoid errors.
- Misinterpretation of divisions: Ensure that the number of Vernier divisions and main-scale divisions are correctly matched (here, 50 Vernier divisions = 49 main-scale divisions).
Exam Tip: When solving Vernier constant problems, always write down the given data clearly and derive the value step-by-step. This minimizes errors and ensures full marks.
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(Least count of Vernier calliper )