JEE PYQ: Units & Measurements - Question ID 1b6c5fdf08ad (JEE Main 2025)
For the determination of refractive index of glass slab, a travelling microscope is used whose main scale contains 300 equal divisions equals to 15 cm . The vernier scale attached to the microscope has 25 divisions equals to 24 divisions of main scale. The least count (LC) of the travelling microscope is (in cm ) :
Select Option
Step-by-step Explanation
In any vernier instrument (such as a travelling microscope), the least count (LC) is the smallest length that can be measured accurately. It is defined as the difference between one main-scale division and one vernier-scale division.
Key formulas:
- Value of one main-scale division (MSD):
- Value of one vernier-scale division (VSD):
- Least count (LC):
Step 1: Compute the value of one main-scale division (MSD)
Given: 300 divisions on the main scale correspond to 15 cm. Therefore,
Step 2: Compute the value of one vernier-scale division (VSD)
The vernier scale has 25 divisions that match 24 divisions of the main scale. Since each main-scale division is 0.05 cm, 24 main-scale divisions equal This 1.2 cm is covered by 25 vernier divisions, so
Step 3: Compute the least count (LC)
The least count is the difference between one main-scale division and one vernier-scale division:
Conclusion: The least count of the travelling microscope is 0.002 cm, which corresponds to option A.
Common Traps & Exam Tip:1. Misidentifying matched divisions: Students often confuse which scale’s divisions match the other. Here, 25 vernier divisions match 24 main-scale divisions, not the other way around. 2. Incorrect unit conversion: Ensure all lengths are in the same unit (cm) before computing. 3. Arithmetic errors: Double-check the subtraction to avoid careless mistakes.
Exam Tip: Always write down the definitions of MSD, VSD, and LC explicitly before plugging in numbers. This keeps the logic clear and reduces errors.
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