JEE PYQ: Units & Measurements - Question ID 0a8925b254f0 (JEE Main 2022)

ID: 0a8925b254f0JEE Main 2022Single Correct MCQ

Identify the pair of physical quantities that have same dimensions:

Select Option

Step-by-step Explanation

Core Formula & Concept:

In dimensional analysis, every physical quantity can be expressed in terms of the fundamental dimensions: mass (MM), length (LL), time (TT), electric current (II), thermodynamic temperature (Θ\Theta), amount of substance (NN), and luminous intensity (JJ). The dimensions of a derived quantity are obtained by expressing it in terms of these base dimensions.

Key formulas and their dimensions relevant to this question:

  • Velocity gradient (GG): G=dvdxG = \frac{dv}{dx}, where vv is velocity and xx is displacement. Dimensions: [LT1][L]=[T1]\frac{[L T^{-1}]}{[L]} = [T^{-1}].
  • Decay constant (λ\lambda): In radioactive decay, the decay law is N=N0eλtN = N_0 e^{-\lambda t}. Since the exponent must be dimensionless, λt\lambda t must be dimensionless. Thus, dimensions of λ\lambda: [T1][T^{-1}].
  • Wien's constant (bb): From Wien's displacement law: λmaxT=b\lambda_{\text{max}} T = b. Dimensions: [LΘ][L \Theta].
  • Stefan constant (σ\sigma): From Stefan-Boltzmann law: E=σT4E = \sigma T^4. Dimensions: [MT3Θ4][L2][L2]=[MT3Θ4]\frac{[M T^{-3} \Theta^{-4}] \cdot [L^2]}{[L^2]} = [M T^{-3} \Theta^{-4}].
  • Angular frequency (ω\omega): ω=2πf\omega = 2\pi f, where ff is frequency. Dimensions: [T1][T^{-1}].
  • Angular momentum (LL): L=mvrL = mvr, where mm is mass, vv is velocity, rr is radius. Dimensions: [M][LT1][L]=[ML2T1][M] \cdot [L T^{-1}] \cdot [L] = [M L^2 T^{-1}].
  • Wave number (kk): k=2πλk = \frac{2\pi}{\lambda}, where λ\lambda is wavelength. Dimensions: 1[L]=[L1]\frac{1}{[L]} = [L^{-1}].
  • Avogadro number (NAN_A): Number of entities per mole. Dimensions: [N1][N^{-1}] (since it's a count per mole, and mole is amount of substance).
Step-by-Step Derivation:

We compare the dimensions of each pair in the options:

  1. Option A: Velocity gradient and decay constant
    Velocity gradient: [T1][T^{-1}]
    Decay constant: [T1][T^{-1}]
    Dimensions match.
  2. Option B: Wien's constant and Stefan constant
    Wien's constant: [LΘ][L \Theta]
    Stefan constant: [MT3Θ4][M T^{-3} \Theta^{-4}]
    Dimensions do not match.
  3. Option C: Angular frequency and angular momentum
    Angular frequency: [T1][T^{-1}]
    Angular momentum: [ML2T1][M L^2 T^{-1}]
    Dimensions do not match.
  4. Option D: Wave number and Avogadro number
    Wave number: [L1][L^{-1}]
    Avogadro number: [N1][N^{-1}]
    Dimensions do not match.

Only Option A has two physical quantities with the same dimensions.

Common Traps & Exam Tip:

Students often confuse:

  • Angular frequency (ω\omega) and angular momentum (LL): Both have "angular" in their names, but their dimensions differ. ω\omega is [T1][T^{-1}], while LL is [ML2T1][M L^2 T^{-1}].
  • Wave number (kk) and Avogadro number (NAN_A): Both involve "number," but wave number is spatial frequency ([L1][L^{-1}]), while Avogadro number is a count per mole ([N1][N^{-1}]).
  • Decay constant (λ\lambda) and velocity gradient (dv/dxdv/dx): Both have dimensions [T1][T^{-1}], but students may overlook the physical meaning and assume they differ.

Exam Tip: Always write down the dimensional formula for each quantity before comparing. Avoid relying on intuition or similar-sounding names.

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