JEE PYQ: Units & Measurements - Question ID 06c11ac25a42 (JEE Main 2020)

ID: 06c11ac25a42JEE Main 2020Single Correct MCQ
A physical quantity z depends on four observables
a, b, c and d, as z = a2b23cd3{{{a^2}{b^{{2 \over 3}}}} \over {\sqrt c {d^3}}}. The percentages of error in the measurement of a, b, c and d are 2%, 1.5%, 4% and 2.5% respectively. The percentage of error in z is :

Select Option

Step-by-step Explanation

Core Formula & Concept:

In experimental physics, when a derived quantity \( z \) is expressed as a product or quotient of several measured observables \( a, b, c, \dots \), the relative error (or percentage error) in \( z \) is determined using the propagation of errors formula. The key principle is:

  • If \( z = k \cdot a^{x} \cdot b^{y} \cdot c^{z} \cdot d^{w} \) (where \( k \) is a dimensionless constant), then the relative error in \( z \) is: Δzz=xΔaa+yΔbb+zΔcc+wΔdd\frac{\Delta z}{z} = |x| \frac{\Delta a}{a} + |y| \frac{\Delta b}{b} + |z| \frac{\Delta c}{c} + |w| \frac{\Delta d}{d}
  • The percentage error in \( z \) is then: % error in z=(Δzz)×100%\% \text{ error in } z = \left( \frac{\Delta z}{z} \right) \times 100\%

This formula arises from logarithmic differentiation, ensuring that errors in each observable contribute proportionally to their exponents.

--- Step-by-Step Derivation:

Given the physical quantity:

z=a2b23cd3z = \frac{a^2 \cdot b^{\frac{2}{3}}}{\sqrt{c} \cdot d^3}

Rewrite \( z \) in exponential form for clarity:

z=a2b23c12d3z = a^2 \cdot b^{\frac{2}{3}} \cdot c^{-\frac{1}{2}} \cdot d^{-3}

Let the percentage errors in \( a, b, c, d \) be:

  • \( \frac{\Delta a}{a} \times 100\% = 2\% \) ⇒ \( \frac{\Delta a}{a} = 0.02 \)
  • \( \frac{\Delta b}{b} \times 100\% = 1.5\% \) ⇒ \( \frac{\Delta b}{b} = 0.015 \)
  • \( \frac{\Delta c}{c} \times 100\% = 4\% \) ⇒ \( \frac{\Delta c}{c} = 0.04 \)
  • \( \frac{\Delta d}{d} \times 100\% = 2.5\% \) ⇒ \( \frac{\Delta d}{d} = 0.025 \)

Apply the error propagation formula:

Δzz=2Δaa+23Δbb+12Δcc+3Δdd\frac{\Delta z}{z} = \left| 2 \right| \frac{\Delta a}{a} + \left| \frac{2}{3} \right| \frac{\Delta b}{b} + \left| -\frac{1}{2} \right| \frac{\Delta c}{c} + \left| -3 \right| \frac{\Delta d}{d}

Substitute the relative errors:

Δzz=2(0.02)+23(0.015)+12(0.04)+3(0.025)\frac{\Delta z}{z} = 2(0.02) + \frac{2}{3}(0.015) + \frac{1}{2}(0.04) + 3(0.025)

Compute each term:

  • \( 2 \times 0.02 = 0.04 \)
  • \( \frac{2}{3} \times 0.015 = 0.01 \)
  • \( \frac{1}{2} \times 0.04 = 0.02 \)
  • \( 3 \times 0.025 = 0.075 \)

Sum the contributions:

Δzz=0.04+0.01+0.02+0.075=0.145\frac{\Delta z}{z} = 0.04 + 0.01 + 0.02 + 0.075 = 0.145

Convert to percentage error:

% error in z=0.145×100%=14.5%\% \text{ error in } z = 0.145 \times 100\% = 14.5\%

Thus, the correct option is B: 14.5%.

--- Common Traps & Exam Tip:
  • Sign Confusion: Students often forget that exponents in the denominator (like \( \sqrt{c} = c^{-\frac{1}{2}} \)) contribute negatively to the exponent but positively to the error (due to absolute value). Always take the magnitude of the exponent.
  • Fractional Exponents: Misapplying \( \frac{2}{3} \) as \( \frac{3}{2} \) or rounding it incorrectly (e.g., 0.666... vs 0.67) can lead to errors. Use exact fractions.
  • Addition vs Multiplication: Errors are added, not multiplied. A common mistake is to multiply percentage errors, which is incorrect.
  • Unit Consistency: While not directly relevant here, ensure all observables are in consistent units before applying error propagation in practical experiments.

Exam Tip: Always write down the formula for error propagation explicitly before substituting values. This avoids sign errors and ensures clarity.

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