JEE PYQ: Motion in a Straight Line - Question ID 04fa630b57cd (JEE Main 2023)

ID: 04fa630b57cdJEE Main 2023Single Correct MCQ

A particle starts with an initial velocity of 10.0 ms110.0 \mathrm{~ms}^{-1} along xx-direction and accelerates uniformly at the rate of 2.0 ms22.0 \mathrm{~ms}^{-2}. The time taken by the particle to reach the velocity of 60.0 ms160.0 \mathrm{~ms}^{-1} is __________.

Select Option

Step-by-step Explanation

Core Formula & Concept:

In problems involving uniformly accelerated motion in a straight line, the relationship between velocity, acceleration, and time is governed by the first equation of kinematics:

v=u+atv = u + a t

where:

  • vv = final velocity (in ms1\mathrm{ms}^{-1})
  • uu = initial velocity (in ms1\mathrm{ms}^{-1})
  • aa = uniform acceleration (in ms2\mathrm{ms}^{-2})
  • tt = time taken (in seconds)
This equation assumes that acceleration is constant and motion occurs along a straight line.

Step-by-Step Derivation:

Given data from the question:

  • Initial velocity, u=10.0 ms1u = 10.0 \mathrm{~ms}^{-1}
  • Acceleration, a=2.0 ms2a = 2.0 \mathrm{~ms}^{-2}
  • Final velocity, v=60.0 ms1v = 60.0 \mathrm{~ms}^{-1}

We are to find the time tt taken to reach v=60.0 ms1v = 60.0 \mathrm{~ms}^{-1}.

Start with the kinematic equation:

v=u+atv = u + a t

Rearrange to solve for tt:

vu=atv - u = a t t=vuat = \frac{v - u}{a}

Substitute the known values:

t=60.010.02.0t = \frac{60.0 - 10.0}{2.0} t=50.02.0t = \frac{50.0}{2.0} t=25.0 secondst = 25.0 \text{ seconds}

Thus, the time taken by the particle to reach 60.0 ms160.0 \mathrm{~ms}^{-1} is 25 seconds.

Common Traps & Exam Tip:

Students often make the following mistakes in such problems:

  • Incorrect sign handling: If acceleration is in the same direction as velocity, it should be taken as positive. Some students mistakenly use negative acceleration, leading to wrong time values.
  • Unit confusion: Mixing up units (e.g., using cm/s\mathrm{cm/s} instead of m/s\mathrm{m/s}) can lead to incorrect numerical results. Always ensure all units are consistent.
  • Misapplying formulas: Using v2=u2+2asv^2 = u^2 + 2 a s (which involves displacement) instead of v=u+atv = u + a t is a common error when time is the unknown. Choose the correct kinematic equation based on the given and required quantities.
  • Arithmetic errors: Simple subtraction or division errors (e.g., 6010=4060 - 10 = 40, then 40/2=2040 / 2 = 20) can lead to selecting option B (6s) or C (3s) instead of the correct D (25s). Always double-check calculations.

Exam Tip: Always write down the known values and the formula before substituting. This helps in avoiding confusion and ensures clarity in problem-solving.

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